Joules to Foot-pounds Converter

To convert a measurement in joules to foot-pounds, multiply the value by 0.737562149277. The conversion factor comes from the relationship between both units and the joule.

For example, to convert 5 J to foot-pounds: 5 × 0.737562149277 = 3.687811 ft·lb.

A joule is the SI derived unit of energy, equal to the work done when a force of one newton moves an object one meter (1 N·m). Named after the English physicist James Prescott Joule, who established the mechanical equivalent of heat in the 1840s. The joule became the SI standard for all forms of energy, work, and heat.

Common uses of joules include: Scientific and engineering energy calculations; Nutrition labeling in metric countries; Mechanical work and kinetic energy; Electrical energy in physics (watt-seconds).

A foot-pound is an imperial unit of energy equal to the work done when a force of one pound-force acts through a distance of one foot, about 1.356 joules. The foot-pound comes from imperial mechanics and is still used in the US for torque and energy, notably to describe the muzzle energy of firearms and the output of engines.

Common uses of foot-pounds include: Firearm muzzle energy; Torque specifications (as ft·lbf); Mechanical work in imperial units; Engine and tool energy ratings.

Here are some common values converted:

1 J = 0.737562149277 ft·lb 5 J = 3.687811 ft·lb 10 J = 7.375621 ft·lb 50 J = 36.878107 ft·lb 100 J = 73.756215 ft·lb